[tex]\frac{y}{y+3} = 10 \ \ \ |\cdot (y+3)\\\\Z: \ y \neq -3\\\\10(y+3) = y\\\\10y + 30 = y\\\\10y-y = -30\\\\9y = -30 \ \ \ |:9\\\\\boxed{y = -\frac{30}{9} = -3\frac{1}{3}}[/tex]
[tex]Z: y \neq -3\\\\\frac{y}{y+3} = 10|*(y+3)\\\\y = 10y + 30 |-10y\\\\-9y = 30 | :(-9)\\\\y = -\frac{30}{9} = -\frac{10}{3}[/tex]
