Odpowiedź:
[tex]a)1dm \times 15cm \times 2dm = \\ = 10cm \times 15cm \times 20cm \\ \\pole \: p. = 2(10 \times 15) + 2(10 \times 20) + 2(15 \times 20) = \\ = 2 \times 150 + 2 \times 200 + 2 \times 300 = \\ = 300 + 400 + 600 = \\ = 1300( {cm}^{2} )[/tex]
[tex]b)2m \times 3cm \times 4dm = \\ = 200cm \times 3cm \times 40cm \\ \\ pole \: p. = 2(200 \times 3) + 2(200 \times 40) + 2(3 \times 40) = \\ = 2 \times 600 + 2 \times 8000 + 2 \times 120 = \\ = 1200 + 1600 + 240 = \\ = 3040( {cm}^{2} )[/tex]
