Odpowiedź :
A. [tex]3\sqrt{2}\cdot3\sqrt{5}=3\cdot3\sqrt{2\cdot5}=\boxed{9\sqrt{10}}[/tex]
B. [tex]3\sqrt{3}\cdot3\sqrt{9}=3\sqrt{3}\cdot3\cdot3=3\sqrt{3}\cdot9=\boxed{27\sqrt{3}}[/tex]
C. [tex]3\sqrt{7}\cdot3\sqrt{7}\cdot3\sqrt{7}=3\cdot3\cdot7\cdot3\sqrt{7}=9\cdot7\cdot3\sqrt{7}=63\cdot3\sqrt{7}=\boxed{189\sqrt{7}}[/tex]
D. [tex]3\sqrt{2}\cdot3\sqrt{5}\cdot3\sqrt{6}=3\cdot3\cdot3\sqrt{2\cdot5\cdot6}=9\cdot3\sqrt{60}=27\sqrt{4\cdot15}=27\cdot2\sqrt{15}=\boxed{54\sqrt{15}}[/tex]
Odpowiedź:
A.
3√2*3√5 = 3 * 3 * √(2*5) = 9√10
B.
3√3*3√9 = 3 * 3 * 3√3 = 27√3 1897
C
.3√7*3√7*3√7 = 3 * 3 * 3√(7*7*7) = 27√(49*7) = 27 * 7√7 = 189√7
D.
3√2*3√5*3√6 = 3 * 3 * 3 * √(2*5*6) = 27√60
Szczegółowe wyjaśnienie: