[tex]1)\\x_1=1, x_2=-3\\\\2)\\y=1(x-2)(x+2)=(x-2)(x+2)\\\\3)\\f(x)=2(x-2)(x+4)=2(x^2+4x-2x+8)=2(x^2+2x+8)=2x^2+4x+16\\\\4)\\\Delta=(-2)^2-4\cdot1\cdot(-3)=4+12=16\\\\\sqrt{\Delta}=\sqrt{16}=4\\\\x_1=\frac{2-4}{2}=\frac{-2}{2}=-1\\\\x_2=\frac{2+4}{2}=\frac{6}{2}=3[/tex]
[tex]y=(x+1)(x-3)[/tex]
Obliczenia do 1)
[tex]2(x-1)(x+3)=0\ \ \ |:2\\\\(x-1)(x+3)=0\\\\x-1=0 \ \ \ lub\ \ \ x+3=0\\\\x=1\ \ \ \ \ \ \ \ \ \ \ \ x=-3[/tex]
