[tex]a) = \sqrt{12} = 2\sqrt{3}\\b) = 2\sqrt{3} * 3\sqrt{2} = 6\sqrt{6}\\c) = 3\frac{1}{2}\sqrt{50} = 17\frac{1}{2}\sqrt{2}\\d) = 5\sqrt{2} + \sqrt{2} = 6\sqrt{2}\\e) = 10\sqrt{3} - 2\sqrt{3} = 8\sqrt{3}\\f) = -8\sqrt{2} - 4\sqrt{2} = -12\sqrt{2}[/tex]