Odpowiedź :
[tex]5\frac{4}{5}-1\frac{1}{7}\cdot4,9 = \frac{29}{5}-\frac{8}{7}\cdot\frac{49}{10} = \frac{29}{5}-4\cdot\frac{7}{5} = \frac{29}{5}-\frac{28}{5} = \frac{1}{5}[/tex]
Odpowiedź:
5 4/5-1 1/7×4 9/10
5 4/5- 8/7×49/10=
29/5-28/5=1/5
[tex]5\frac{4}{5}-1\frac{1}{7}\cdot4,9 = \frac{29}{5}-\frac{8}{7}\cdot\frac{49}{10} = \frac{29}{5}-4\cdot\frac{7}{5} = \frac{29}{5}-\frac{28}{5} = \frac{1}{5}[/tex]
Odpowiedź:
5 4/5-1 1/7×4 9/10
5 4/5- 8/7×49/10=
29/5-28/5=1/5