[tex] \huge{\boxed{Odp.C}}[/tex]
Pole powierzchni bocznej
[tex]Pb = 3 \times \frac{4 \times 8}{2} = 3 \times \frac{32}{2} = 3 \times 16 = 48[/tex]
Pole podstawy
[tex]Pp = \frac{ {4}^{2} \sqrt{3} }{4} = \frac{16 \sqrt{3} }{4} = 4 \sqrt{3} [/tex]
Pole całkowite
[tex]Pc = 4 \sqrt{3} + 48[/tex]
