Odpowiedź:
a)
(x – 4)(2x + 6)(x^2 - 9) = 0
(x – 4)(2x + 6)(x+3)(x-3) = 0
x-4=0 v 2x+6=0 v x+3=0 v x-3=0
x=4 v x=-3 v x=-3 v x=3
x= {-3, 3, 4}
b)
3x^4 – 18x^3 +27x^2 = 0
3x²(x²-6x+9)=0
3x²(x-3)²=0
3x²=0 v x-3=0
x=0 v x=3
x= {0,3}
c)
x^3 – 2x^2 - 9x + 18 = 0
x²(x-2)-9(x-2)=0
(x²-9)(x-2)=0
(x+3)(x-3)(x-2)=0
x+3=0 v x-3=0 v x-2=0
x=-3 v x=3 v x=2
x= {-3,2,3}
