[tex]przeciwprostokatna\ trojkatna\ prostokatnego :\ \ c=10\\\\przyprostokatna\ a=2\sqrt{10}\\\\przyprostokatna\ b=?\\\\stosujemy\ tw.\ Pitagorasa\\\\ a^2+b^2=c^2\\\\b^2=c^2-a^2\\\\b^2=10^2-(2\sqrt{10})^2 \\\\b^2=100-40\\\\b^2=60\\\\b=\sqrt{60}=\sqrt{4*15}=2\sqrt{15}\\\\ pole\ trojkata\ prostpkatnego:\\\\ P=\frac{1}{2}a*b\\\\P=\frac{1}{\not{2}^1}*\not{2}^1\sqrt{10}* 2\sqrt{15}=2\sqrt {10*15}=2\sqrt{150}=2\sqrt{25*6}=\\\\=2*5\sqrt{6}=10\sqrt{6}\ [j^2][/tex]
[tex]odp.\ Pole\ tego\ trojkata\ prostokatnego \ wynosi\ 10\sqrt{6}\ [j^2].[/tex]
