Odpowiedź: zadanie nr 1
a) sin a = c/b
cos a = a/b
tg a = c/a
ctg a = a/c
b) sin a = y/z
cos a = x/z
tg a = y/x
ctg a = x/y
c) sin a = l/m
cos a = k/m
tg a = l/k
ctg a = k/l
d) sin a = b/a
cos a = k/a
tg a = b/k
ctg a = k/b
e) sin a = g/x
cos a = z/x
tg a = g/z
ctg a = z/g
Szczegółowe wyjaśnienie:
