Odpowiedź:
[tex]g_M=0,35g_z[/tex]
Wyjaśnienie:
Dane:
[tex]R_M=\frac{2}{5}R_z[/tex]
[tex]M_M=\frac{1}{18}M_z[/tex]
Szukane: [tex]\frac{g_z}{g_M}[/tex]
[tex]mg=\frac{GmM}{R^2}/:m[/tex]
[tex]g_z=\frac{GM_z}{R_2^2}[/tex]
[tex]g_M=\frac{GM_M}{R_M^2}=\frac{G*\frac{1}{18}M_z }{(\frac{2}{5}R_z )^2}=\frac{\frac{1}{18} }{\frac{4}{25} }*\frac{GM_z}{R_z^2}=\frac{1}{18}*\frac{25}{4}*g_z=\frac{25}{72}g_z[/tex]
[tex]g_M\approx0,35g_z[/tex]
