Odpowiedź :
Odpowiedź:
a - bok kwadratu
d - przekątna kwadratu = a√2
a)
d = a√2 = 7√2 cm
a= 7√2/√21cm= 7cm
o - obwód = 4a = 4 * 7 cm = 28cm
P - pole = a² = 7² cm² = 49 cm²
b)
d = a√2 = 4 dm
a = 4/√2 dm = 4√2/2 dm = 2√2 dm
o = 4 * 2√2dm= 8√2dm
P= a²= (2√2)² dm = (4 * 2) dm² = 8dm²
c)
d = a√2 = 12 m
a = 12/√2 m = 12√2/2 m = 6√2 m
o = 4 * 6√2 m = 24√2 m
P = a² = (6√2)² m²= (36 * 2) m² = 72m²
Odpowiedź:
a) d=7[tex]\sqrt{2}[/tex]
d=a[tex]\sqrt{2}[/tex]
[tex]a \sqrt{2} = 7\sqrt{2}\\ a=7[/tex]
P = a *a = 7 * 7 = 49 cm2
obw = 4a = 4 * 7 = 28 cm
b) d=4 dm
d=[tex]a\sqrt{2}[/tex]
[tex]a\sqrt{2} = 4 / \sqrt{2}[/tex]
[tex]a = \frac{4}{\sqrt{2}}[/tex]
musimy uwolnić ułamek od niewymierności więc
[tex]a = \frac{4}{\sqrt{2} } * \frac{\sqrt{2} }{\sqrt{2} } = \frac{4\sqrt{2} }{2} = 2\sqrt{2}[/tex]
P = a*a = 2[tex]\sqrt{2}[/tex] * 2[tex]\sqrt{2}[/tex] = 8 dm2
Obw= 4a = 4* 2[tex]\sqrt{2}[/tex] = 8[tex]\sqrt{2}[/tex] dm
c) d=12m
d=[tex]a\sqrt{2}[/tex]
[tex]a\sqrt{2} = 12 / \sqrt{2}[/tex]
[tex]a = \frac{12}{\sqrt{2}}[/tex]
musimy uwolnić ułamek od niewymierności więc
[tex]a = \frac{12}{\sqrt{2} } * \frac{\sqrt{2} }{\sqrt{2} } = \frac{12\sqrt{2} }{2} = 6\sqrt{2}[/tex]
P = a*a = 6[tex]\sqrt{2}[/tex] * 6[tex]\sqrt{2}[/tex] = 72 m2
Obw= 4a = 4* 6[tex]\sqrt{2}[/tex] = 24[tex]\sqrt{2}[/tex] m
Szczegółowe wyjaśnienie: