[tex]\begin{cases}x-\frac{4x-2}{3}\geq x-6 \ \ |*3\\ 1-(2x-1)(2x+1)<-2x-(2x-1)^2 \end{cases } \\\\ \begin{cases}3x- (4x-2 ) \geq 3x-18 \\ 1-(4x^2-1) <-2x-(4x^2-4x+1) \end{cases}\\\\\begin{cases}x- 4x +2\geq 3x -18 \\ 1- 4x^2+1 <-2x- 4x^2+4x-1 \end{cases}[/tex]
[tex]\begin{cases} -x +2\geq 3x -18 \\ - 4x^2+2 <- - 4x^2+2x-1 \end{cases}\\\\ \begin{cases} -x -3x\geq -18-2 \\ - 4x^2+4x^2-2x < -1-2 \end{cases}\\\\ \begin{cases} -4x\geq -20\ \ |:(-4) \\ -2x < -3 \ \ |:(-2)\end{cases}[/tex]
[tex]\begin{cases} x \leq 5\\ x > \frac{3 }{2} \end{cases}[/tex]
[tex]x\in(\frac{3}{2},5>[/tex]
