[tex]4^{-3} = \frac{1}{64}\\64x^{\frac{-2}{3} } = \frac{1}{\sqrt[3]{64^{2}}} = \frac{1}{\sqrt[3]{4096}} = \frac{1}{16}\\(\frac{3}{2})^{-2} = \frac{4}{9}\\(1\frac{3}{2})^{-2}= 6.25\\4^{\frac{-3}{2} } = 2\sqrt[3]{2} \\9^{-3}:9^{-5}=9^{-8}\\(\sqrt[3]{2})^{6} = 4\\5:5^{-2} = 5^3[/tex]
