Odpowiedź:
[tex](3-2x)(3+2x)-(2x-1)^2=9+6x-6x-4x^2-(4x^2-4x+1)=\\\\=9-4x^2-4x^2+4x-1=-8x^2+4x+8\\\\\\dla\ \ x=1+\sqrt{2}\\\\-8x^2+4x+8=-8\cdot(1+\sqrt{2})^2+4(1+\sqrt{2})+8=-8(1+2\sqrt{2}+2)+4+4\sqrt{2}+8=\\\\=-8(3+2\sqrt{2)}+12+4\sqrt{2}=-24-16\sqrt{2}+12+4\sqrt{2}=-12-12\sqrt{2}[/tex]
