1.
[tex]a) \ 15\dfrac{g}{cm^{3}} = 15\cdot\dfrac{\dfrac{1}{1000}kg}{\dfrac{1}{1000 \ dm^{3}}}=15\dfrac{kg}{dm^{3}}\\\\\\b) \ 125\dfrac{g}{dm^{3}} = 125\cdot\dfrac{\dfrac{1}{1000}kg}{\dfrac{1}{1000 \ m^{3}}}=125\dfrac{kg}{m^{3}}\\\\\\c) \ 7,34\dfrac{kg}{dm^{3}}=7,34\cdot\dfrac{1000 \ g}{1000 \ cm^{3}}}=7,34\dfrac{g}{cm^{3}}[/tex]
2.
[tex]Dane:\\d = 4,2\frac{kg}{dm^{3}}\\V = 12 \ dm^{3}}\\szukane:\\m = ?\\\\Rozwiazanie\\\\d = \frac{m}{V} \ \ /\cdot V\\\\m = V\cdot d\\\\m = 12 \ dm^{3}\cdot4,2\frac{kg}{dm^{3}}\\\\\boxed{m = 50,4 \ kg}[/tex]
