mnożymy na krzyż
a)6x=4(x+5) x≠0 x≠-5
6x=4x+20
6x-4x=20
2x=20 |:2
x=10
b)7(x-5)=3(2x-4) x≠2
7x-35=6x-12
7x-6x=-12+35
x=23
c)3(x-6)=5(0,4x-2)
3x-18=2x-10
3x-2x=-10+18
x=8
[tex]d)\frac{3-x^{2}}{x}=\frac{2(-4x+3)}{8}\\\frac{3-x^{2}}{x}=\frac{-4+3}{4} \\4(3-x^{2})=x(-4x+3)\\12-4x^{2}=-4x^{2}+3x\\-3x=-12|:(-3)\\\\x=4[/tex]x≠0
