Obliczenia
[tex]3\frac{2}{3}+1,1=3\frac{2}{3}+1\frac{1}{10}=3\frac{20}{30}+1\frac{3}{30}=4\frac{23}{30}\\\\7,35-1\frac{1}{5}=7,35-1\frac{2}{10}=7,35-1,2=6,15\\\\3\frac{2}{3}\cdot1,2=\frac{11}{3}\cdot1\frac{2}{10}=\frac{11}{\not3_1}\cdot\frac{\not12^4}{10}=\frac{44}{10}=4\frac{4}{10}=4\frac{2}{5}\\\\5\frac{1}{4}:0,125=\frac{21}{4}:\frac{125}{1000}=\frac{21}{4}:\frac{1}{8}=\frac{21}{4}\cdot8=21\cdot2=42[/tex]
