CWICZENIE 4, Oblicz wartość wyrazenia, proszę o pomoc

[tex] \frac{2\frac{6}{10} - 1 \frac{3}{10} }{ \frac{7}{10} + 5 \frac{2}{10} } = \frac{ 1 \frac{3}{10} }{5 \frac{9}{10} } = \frac{13}{10} \times \frac{10}{59} = \frac{13}{59} [/tex]

b.

[tex] \frac{ \frac{6}{42} - \frac{35}{42} }{ \frac{2}{21} + \frac{1}{2} } = \frac{ - \frac{ 29}{42} }{ \frac{4}{42} + \frac{21}{42} } = - \frac{29}{42} \times \frac{42}{25} = - 1 \frac{4}{25} [/tex]

C.

[tex]5 \frac{1}{4} - \frac{1}{4} \times (1 \frac{2}{5} - \frac{3}{5} ) = 5 \frac{1}{4} - \frac{1}{4} \times \frac{4}{5} = 5 \frac{1}{4} - \frac{1}{5} = 5 \frac{5}{20} - \frac{16}{20} = 4 \frac{9}{20} [/tex]

Magdaviz Magdaviz · Answer 2

Odpowiedź:

[tex]a)\ \ \dfrac{2\frac{3}{5}-1,3}{\frac{7}{10}+5,2}=\dfrac{2,6-1,3}{0,7+5,2}=\dfrac{1,3}{5,9}=1,3:5,9=\frac{13}{10}:\frac{59}{10}=\frac{13}{\not10}\cdot\frac{\not10}{59}=\frac{13}{59}\\\\\\b)\ \ \dfrac{\frac{1}{7}-\frac{5}{6}}{\frac{2}{21}+0,5}=\dfrac{\frac{6}{42}-\frac{35}{42}}{\frac{2}{21}+\frac{1}{2}}=\dfrac{-\frac{29}{42}}{\frac{4}{42}+\frac{21}{42}}=\dfrac{-\frac{29}{42}}{\frac{25}{42}}=-\frac{29}{42}:\frac{25}{42}=-\frac{29}{\not42}\cdot\frac{\not42}{25}=-\frac{29}{25}=[/tex]

[tex]=-1\frac{4}{25}\\\\\\c)\ \ 5\frac{1}{4}-0,25\cdot(1,4-\frac{3}{5})=5\frac{1}{4}-\frac{1}{4}\cdot(1,4-0,6)=5\frac{1}{4}-\frac{1}{4}\cdot0,8=5\frac{1}{4}-\frac{1}{\not4}\cdot\frac{\not4}{5}=\\\\=5\frac{1}{4}-\frac{1}{5}=5\frac{5}{20}-\frac{4}{20}=5\frac{1}{20}[/tex]