Odpowiedź:
Energia kinetyczna wzrośnie 3,24 raza.
Wyjaśnienie:
[tex]v_1 = 50\frac{km}{h}\\v_2 = 90\frac{km}{h}\\\frac{E_{k_2}}{E_{k_1}} = ?\\\\E_{k} = \frac{mv^{2}}{2}\\\\E_{k_1} = \frac{mv_1^{2}}{2} = \frac{m\cdot50^{2}}{2}\\\\E_{k_2} = \frac{mv_2^{2}}{2} = \frac{m\cdot90^{2}}{2}\\\\\frac{E_{k_2}}{E_{k_1}} = \frac{\frac{m\cdot90^{2}}{2}}{\frac{m\cdot50^{2}}{2}} = \frac{90^{2}}{50^{2}} = (\frac{9}{5})^{2} = \frac{81}{25} = 3,24\\\\E_{k_2} = 3,24E_{k_1}[/tex]
