te dwa zadania potrzebujee szybkoo, dam najjj​

Te Dwa Zadania Potrzebujee Szybkoo Dam Najjj class=

Odpowiedź :

Odpowiedź:

7.

a) 3^4 * 9^2 = 3^4 * (3^2)^2 = 3^8

b) 4^5 * 8^3 = (2^2)^5 * (2^3)^3 = 2^19

c) 8^3 / 2^5 = (2^3)^3 / 2^5 = 2^4

d) 125^7 / 25^10 = (5^3)^7 / (5^2)^10 = 5^1 (po prostu 5)

e) (1/9)^4 / (1/3)^3 = [(1/3)^2]^4 / (1/3)^3 = (1/3)^5

f) 0,5^9 / (1/4)^4 = 0,5^9 / (0,5^2)^4 = 0,5

g) 0,1^9 / 0,001^2 = 10^-9 / (10^-3)^2 = 10^-3

h) (5^8/32)*(2^10/125) = (5^8/2^5)*(2^10/5^3)= 5^5*2^5 = 10^5

8.

a) (2^10 * 2^5 *7^4)^2 = 2^m * 7^n

(2^15*7^4)^2 = 2^m * 7^n

2^30*7^8 = 2^m * 7^n

m = 30

n = 8

b) [(3^4*5^7)^3]/5^9 = 3^m * 5^n

(3^12*5^21)/5^9 = 3^m * 5^n

3^12 * 5^12 = 3^m * 5^n

m = n = 12

c) 4 * [(2^3/3^4)]^10 = 2^m/3^n

2^2 * (2^30/3^40) = 2^m/3^n

2^32/3^40 = 2^m/3^n

m = 32

n =  40

d) [(7^3/5^2)^3] * [(5^3/7^5)^4] = 5^m/7^n

(7^9/5^6) * (5^12/7^20) = 5^m/7^n

5^7/7^11 = 5^m/7^n

m = 6

n =  11

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