POMOCY!

Z podanego wzoru wyznaczany x.

Y= ax + b

1/x=b

y-1/x+1=7/8​


Odpowiedź :

1.

y=ax+b

ax=y-b |:a , dla a≠0

x=(y-b)/a

2.

1/x=b |·x   ∧ x≠0

1=bx |:b , b≠0

x=1/b

3.

y-1/(x+1)=7/8 |·(x+1)

y(x+1)-1=7/8(x+1)|·8

8y(x+1)=7(x+1)

8xy+8y=7x+7

8xy-7x=7-8y

x(8y-7)=7-8y|:(8y-7)

x=(7-8y)/(8y-7)

x=-(8y-7)/(8y-7)  , dla y≠7/8

x=-1

Viz Inne Pytanie