Odpowiedź:
[tex]-3(y+1)+6y=-2(y-1)\\\\-3y-3+6y=-2y+2\\\\3y-3=-2y+2\\\\3y+2y=2+3\\\\5y=5\ \ /:5\\\\y=1\\\\\\(3x-2)(x+1)=3x^2-5\\\\3x^{2}+3x-2x-2=3x^{2}-5\\\\3x^{2}+x-3x^{2}=-5+2\\\\x=-3[/tex]
[tex]3x(2x+5)=(x+3)(x+1)\\\\6x^2+15x=x^2+x+3x+3\\\\6x^2+15x=x^2+4x+3\\\\6x^2+15x-x^2-4x-3=0\\\\5x^2+11x-3=0\\\\\Delta=b^2-4ac=11^2-4\cdot5\cdot(-3)=121+60=181\\\\\sqrt{\Delta}=\sqrt{181}\\\\\\x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-11-\sqrt{181}}{2\cdot5}=\frac{-11-\sqrt{181}}{10}\\\\x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-11+\sqrt{181}}{2\cdot5}=\frac{-11+\sqrt{181}}{10}[/tex]
[tex]\frac{x+1}{2}-\frac{x-1}{3}=\frac{1}{4}\ \ /\cdot12\\\\6(x+1)-4(x-1)=3\\\\6x+6-4x+4=3\\\\2x+10=3\\\\2x=3-10\\\\2x=-7\ \ /:2\\\\x=-\frac{7}{2}\\\\x=-3\frac{1}{2}[/tex]
