[tex]dane:\\m = 1 \ t = 1000 \ kg\\v = 15\frac{m}{s}\\g = 10\frac{N}{kg}\\szukane:\\P = ?\\\\Rozwiazanie\\\\P = \frac{W}{t}\\\\W = F\cdot s, \ wiec\\\\P = \frac{F\cdot s}{t}\\\\v = \frac{s}{t}, \ zatem\\\\P = F\cdot v\\\\F = m\cdot g = 1000 \ kg\cdot10\frac{N}{kg} = 10 \ 000 \ N\\\\P = 10 \ 000 \ N\cdot 15\frac{m}{s}\\\\P = 150 \ 000 \ W = 150 \ kW[/tex]
Odp. Dźwig ma moc P = 150 kW.
