Imking4viz
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9 i 10. Dam naj!....

9 I 10 Dam Naj class=

Odpowiedź :

Matfizianka06viz

Odpowiedź:

[tex]9. \: \sqrt{40} + \sqrt{90} = \sqrt{4 \times 10} + \sqrt{9 \times 10} = 2 \sqrt{10} + 3 \sqrt{10} = 5 \sqrt{10} [/tex]

[tex]10. \: \sqrt[3]{270} + \sqrt[3]{80} = \sqrt[3]{27 \times 10} + \sqrt[3]{8 \times 10} = 3 \sqrt[3]{10} + 2 \sqrt[3]{10} = 5 \sqrt[3]{10} = \sqrt[3]{125 \times 10} = \sqrt[3]{1250} [/tex]

Basetlaviz

9.

[tex]\sqrt{40}+\sqrt{90} = \sqrt{4\cdot10} + \sqrt{9\cdot10} = 2\sqrt{10}+3\sqrt{10} = 5\sqrt{10} =\\\\= \sqrt{5^{2}\cdot10} = \sqrt{25\cdot10} = \sqrt{250}[/tex]

10.

[tex]\sqrt[3]{270}+\sqrt[3]{80} = \sqrt[3]{27\cdot10} + \sqrt[3]{8\cdot10} = 3\sqrt[3]{10}+2\sqrt[3]{10} = 5\sqrt[3]{10}=\\\\=\sqrt[3]{5^{3}\cdot10} = \sqrt[3]{125\cdot10} = \sqrt[3]{1250}[/tex]

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