bok kwadratu a
obwod kwadratu O₁=4a=24
a=6
boki prostokata m,n
obwod prostokata O₂=2m+2n=24
m+n=12
m=12-n
pole kwadratu P₁=a²
pole prostokata P₂=m*n
mamy P₁=P₂+16
a²=m*n+16
6²=(12-n)n+16
36=12n-n²+16
n²-12n+20=0
Δ=12²-4*20=144-80=64
√Δ=8
n₁=(12-8)/2=4/2=2
n₂=(12+8)/2=10
m₁=10
m₂=2
boki prostokata sa rowne 2,10
