log5 + log8 - 2log2

Odpowiedź :

log(5x8) - 2log2 = log(40:[2x2]) = log10= 1
log5 + log8 - 2log2=log5+log8-log2²=log5+log8-log4=log(5*8)-log4=log40-log4=log(40:4)=log10=1
bo log10=log₁₀10, więc log₁₀10=y, więc 10^y=10, więc y=1