(√2) do -8 potegi = [ 2^(1/2)]^(-8) = 2^(1/2 * (-8)) = 2^(-4) = (1/2)^4 = 1/16
[tex](\sqrt{2})^{-8} = (2^{\frac{1}{2})^{-8}}} = 2^{\frac{-8}{2}} = 2^{-4} = \frac{1}{2^4} = \frac{1}{16}[/tex]
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
