Odpowiedź :
[tex]a)\\\\4\frac56*\frac{5}{27} \\\text{Czynnik 1: } 4\frac56\\\text{Czynnik 2: } \frac5{27}\\4\frac56:\frac5{27} = \frac{29}6*\frac{27}5=\frac{29}2*\frac95=26.1[/tex]
[tex]b)\\\\3\frac34*\frac3{14}\\\text{Czynnik 1: } 3\frac34\\\text{Czynnik 2:} \frac3{14}\\3\frac34:\frac3{14}=\frac{15}4*\frac{14}3=\frac52*\frac71=\frac{35}2=17.5[/tex]
[tex]c)\\\\5\frac16*1\frac35\\\text{Czynnik 1: } 5\frac16\\\text{Czynnik 2: } 1\frac35\\5\frac16:1\frac35=\frac{31}6:\frac85=\frac{31}6*\frac58=\frac{155}{48}=3\frac{11}{48}[/tex]
[tex]d)\\\\3\frac37*3\frac14\\\text{Czynnik 1: } 3\frac37\\\text{Czynnik 2: } 3\frac14\\3\frac37:3\frac14=\frac{24}7:\frac{13}4=\frac{24}7*\frac4{13}=\frac{96}{91}=1\frac5{91}[/tex]