[tex]Dane:\\m = 2 \ kg\\v=2\frac{m}{s}\\g = 10\frac{m}{s^{2}}\\Szukane:\\h = ?\\\\Rozwiazanie\\\\Z \ zasady \ zachowania \ energii\\\\E_{p} = E_{k}\\\\mgh = \frac{mv^{2}}{2} \ \ \ |:mg\\\\h =\frac{v^{2}}{2g}\\\\h = \frac{(2\frac{m}{s})^{2}}{2\cdot10\frac{m}s^{2}}=\frac{4\frac{m^{2}}{s^{2}}}{20\frac{m}{s^{2}}}\\\\\boxed{h = 0,2 \ m}[/tex]
