Odpowiedź:
[tex]a) \: \: \sqrt{12} = \sqrt{4 \cdot3} = \sqrt{ {2}^{2} \cdot3} = \sqrt{ {2}^{2} } \cdot \sqrt{3} = 2 \sqrt{3} [/tex]
[tex]b) \: \: \sqrt{28} = \sqrt{4 \cdot7} = \sqrt{ {2}^{2} \cdot7} = \sqrt{ {2}^{2} } \cdot \sqrt{7} = 2 \sqrt{7} [/tex]
[tex]c) \: \: \sqrt{80} = \sqrt{16 \cdot5} = \sqrt{ {4}^{2} \cdot5} = \sqrt{ {4}^{2} } \cdot \sqrt{5} = 4 \sqrt{5} [/tex]
[tex]d) \: \: \sqrt{125} = \sqrt{25 \cdot5} = \sqrt{ {5}^{2} \cdot5} = \sqrt{ {5}^{2} } \cdot \sqrt{5} = 5 \sqrt{5} [/tex]
[tex]e) \: \: \sqrt[3]{32} = \sqrt[3]{8\cdot4} = \sqrt[3]{ {2}^{3} \cdot4 } = \sqrt[3]{ {2}^{3} } \cdot \sqrt[3]{4} = 2\sqrt[3]{4} [/tex]
[tex]f) \: \: \sqrt[3]{54} = \sqrt[3]{27 \cdot2} = \sqrt[3]{ {3}^{3} \cdot2 } = \sqrt[3]{ {3}^{3} } \cdot \sqrt[3]{2} = 3 \sqrt[3]{2} [/tex]
[tex]g) \: \: \sqrt[3]{ - 16} = \sqrt[3]{ - 8 \cdot2} = \sqrt[3]{ - {2}^3 \cdot2} = \sqrt[3]{ - {2}^{3} } \cdot \sqrt[3]{2} = - 2 \sqrt[3]{2} [/tex]
[tex]h) \: \: \sqrt[3]{ - 128} = \sqrt[3]{64 \cdot2} = \sqrt[3] {4^3 \cdot2} = \sqrt[3] {4^{3} } \cdot \sqrt[3]{2} = 4 \sqrt[3]{2} [/tex]
