Odpowiedź:
[tex]a)\ \ 0,2\cdot(-3\frac{1}{4}+\frac{1}{4})=0,2\cdot(-3)=-0,6\\\\\\b)\ \ 2,25\cdot3\frac{1}{5}-1,3=\frac{225}{100}\cdot\frac{16}{5}-1,3=\frac{9}{\not4_{1}}\cdot\frac{\not16^4}{5}-1,3=\frac{36}{5}-1,3=7\frac{1}{5}-1,3=\\\\=7,2-1,3=5,9\\\\\\c)\ \ \frac{1}{2}+1\frac{1}{2}:6=\frac{1}{2}+\frac{\not3^1}{2}\cdot\frac{1}{\not6_{2}}=\frac{1}{2}+\frac{1}{4}=\frac{2}{4}+\frac{1}{4}=\frac{3}{4}\\\\\\d)\ \ 2,6:0,1-0,1:\frac{1}{60}=26:1-0,1\cdot60=26-6=20[/tex]
[tex]e)\ \ \dfrac{1\frac{1}{3}-2}{1-\frac{2}{3}}=\dfrac{\frac{4}{3}-\frac{6}{3}}{\frac{3}{3}-\frac{2}{3}}=\dfrac{-\frac{2}{3}}{\frac{1}{3}}=-\frac{2}{3}:\frac{1}{3}=-\frac{2}{\not3}\cdot\not3=-2\\\\\\f)\ \ \dfrac{\frac{1}{5}-\frac{1}{6}}{2-1,8}=\dfrac{\frac{6}{30}-\frac{5}{30}}{0,2}=\dfrac{\frac{1}{30}}{0,2}=\frac{1}{30}:0,2=\frac{1}{30}:\frac{2}{10}=\frac{1}{30}:\frac{1}{5}=\frac{1}{\not30_{6}}\cdot\not5^1=\frac{1}{6}[/tex]
[tex]g)\ \ \dfrac{0,3-1,2}{\frac{9}{4}\cdot(0,2-\frac{3}{4})}=\dfrac{-0,9}{\frac{9}{4}\cdot(\frac{1}{5}-\frac{3}{4})}=\dfrac{-0,9}{\frac{9}{4}\cdot(\frac{4}{20}-\frac{15}{20})}=\dfrac{-0,9}{\frac{9}{4}\cdot(-\frac{11}{20})}=\dfrac{-0,9}{-\frac{99}{80}}=\\\\\\=0,9:\frac{99}{80}=\frac{\not9^1}{\not10_{1}}\cdot\frac{\not80^8}{\not99_{11}}=\frac{8}{11}[/tex]
