[tex]7 - \frac{6 + x}{3} = 2(x - 1) + 7 | \times 3 \\ 21 - 1(6 + x) = 6(x - 1) + 21 \\ 21 - 6 - x = 6x - 6 + 21 \\ 15 - x - 6x = 15 \\ - 7x = 0 | \div ( - 7) \\ x = 0[/tex]
Sprawdzenie
[tex]7 - \frac{6 + 0}{3} = 2(0 - 1) + 7 \\ 7 - \frac{6}{3} = 2 \times ( - 1) + 7 \\ 7 - 2 = - 2 + 7 \\ 5 = 5 \\ L = P[/tex]
Odpowiedź:
7 - (6 + x)/3 = 2(x - 1) + 7
7 - 2 - 1/3x = 2x - 2 + 7
5 - 1/3x = 2x + 5
-1/3x - 2x = 5 - 5
-2 1/3x = 0
-7/3x = 0 /*(-3/7)
x = 0
spr.
L = 7 - (6 + 0)/3 = 7 - 2 = 5
P = 2(0 - 1) + 7 = -2 + 7 = 5
L = P
Szczegółowe wyjaśnienie:
