[tex]Dane:\\P = 60 \ W\\I = 0,3 \ A\\Szukane:\\R = ?\\\\Rozwiazanie\\\\P =U\cdot I\\\\ale \ \ U = I\cdot R, \ zatem\\\\P = I^{2}\cdot R \ \ |:I^{2}\\\\R = \frac{P}{I^{2}}\\\\R = \frac{60}{0,3^{2}} \ \ [\Omega]\\\\R = 666,(6) \ \Omega\approx667 \ \Omega[/tex]
