Odpowiedź :
Odpowiedź:
f(x)= - x² + bx + c
a = - 1
x₁ = 3 , x₂ = 6
f(x) = a(x -x₁)(x - x₂) = - (x - 3)(x - 6) = - (x² - 3x - 6x + 18) = - (x² - 9x + 18) =
= - x² + 9x - 18
b = 9 , c = - 18
Odpowiedź:
[tex]f(x)=-x^2+bx+c\\\\x_{1}=3\ \ i\ \ x_{2}=6\\\\a=-1\\\\\\f(x)=-1(x-x_{1})(x-x_{2})\\\\f(x)=-(x-x_{1})(x-x_{2})\\\\f(x)=-(x-3)(x-6)\\\\f(x)=-(x^2-6x-3x+18)\\\\f(x)=-(x^2-9x+18)\\\\f(x)=-x^2+9x-18\\\\\\b=9\ \ ,\ \ c=-18[/tex]