[tex]V = \frac{Pp \times H}{3}[/tex]
Pole podstawy
[tex] \frac{ {a}^{2} \sqrt{3} }{4} = \frac{ {16}^{2} \sqrt{3} }{4} = \frac{256 \sqrt{3} }{4} = 64 \sqrt{3} {cm}^{2} [/tex]
Zatem objętość
[tex]V = \frac{64 \sqrt{3} \times 10 }{3} = \frac{640 \sqrt{3} }{3} = \boxed{213 \frac{1}{3} \sqrt{3} {cm}^{3} }[/tex]
