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Rozwiązane

a) -(6y+3)(2x+4y)-30(x-2y)=
b) (6x+12y)(x+2y+5)=
c) (-2a+2c)(4a+4c)=
d) (4x^2+6xy+9y^2)(2x-3y)=
Pls szybko potrzebuje!! Daje naj​

Odpowiedź :

Magdaviz

Odpowiedź:

[tex]a)\ \ -(6y+3)(2x+4y)-30(x-2y)=-(12xy+24y^2+6x+12y)-30x+60y=\\\\=-12xy-24y^2-6x-12y-30x+60y=-12xy-24y^2-36x+48y\\\\\\b)\ \ (6x+12y)(x+2y+5)=6x^2+12xy+30x+12xy+24y^2+60y=\\\\=6x^2+24xy+30x+24y^2+60y\\\\\\c)\ \ (-2a+2c)(4a+4c)=-8a^2-8ac+8ac+8c^2=-8a^2+8c^2[/tex]

[tex]d)\ \ (4x^2+6xy+9y^2)(2x-3y)=8x^3-12x^2y+12x^2y-18xy^2+18xy^2-27y^3=\\\\=8x^3-27y^3[/tex]

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