Odpowiedź:
a)
[tex]-3x+17+x=11x+2+2x\\15x = 15\\ x =1[/tex]
b)
[tex]-3x(2x+5)+4(-x+3)=2(3x-5)\\-6x^2 -15x -4x +12 = 6x - 10\\-6x^2 -25x +22 = 0\\[/tex]
Δ = [tex]625 + 528 = 1153[/tex]
[tex]x_{1} = - \frac{25-\sqrt{1153} }{12} \\x_{2} =- \frac{25+\sqrt{1153} }{12} \\[/tex]
c)
[tex]12(2-3x)-7(x+3)=3(2-10x)-4(2x-1)\\24 - 36x -7x -21 = 6 -30x -8x +4\\-5x =7\\[/tex]
[tex]x = -\frac{7}{5}[/tex]
d)
[tex]6(3x*2)+5(1-3x)=7(x+2)-3(1-2x)\\36x+5-15x=7x+14-3+6x\\8x = 6\\x = \frac{3}{4}[/tex]
Pozdro:)
