Odpowiedź:
Zad2
a) [tex]\sqrt{18} =\sqrt{9*2}=3\sqrt{2\\[/tex]
[tex]\sqrt{8}= \sqrt{4*2}=2 \sqrt{2}[/tex]
[tex]\sqrt{200} =\sqrt{100*2}=10 \sqrt{2}[/tex]
[tex]3\sqrt{2} + 2\sqrt{2} -10\sqrt{2} = -5\sqrt{2}[/tex]
b)[tex]\sqrt[3]{40} =\sqrt[3]{8*5} =2\sqrt[3]{5}[/tex]
[tex]\sqrt[3]{27} =3[/tex]
[tex]2\sqrt[3]{5} +3 -\sqrt[3]{5} = \sqrt[3]{5} + 3[/tex]
zad3
a)[tex]\frac{\sqrt{6} }{2\sqrt{3} } * \frac{\sqrt{3} }{\sqrt{3} } = \frac{\sqrt{6} * \sqrt{3} }{6}[/tex]
b)[tex]\frac{2-2\sqrt{5} }{\sqrt{2} } * \frac{\sqrt{2} }{\sqrt{2} } =\frac{2-2\sqrt{5}* \sqrt{2} }{2}[/tex]
Szczegółowe wyjaśnienie:
