Odpowiedź:
[tex][2x-1;0] = [3;2y +1]\\2x - 1 = 3 \\x = 2\\2y+1 = 0\\y = - \frac{1}{2}[/tex]
[tex]\left \{ {{x=2} \atop {y=-\frac{1}{2} }} \right.[/tex]
D. [tex]x^y = 2^-\frac{1}{2} = \frac{1}{2} ^ \frac{1}{2} = \sqrt{\frac{1}{2} } = \frac{1}{\sqrt{2} }[/tex]
Poprawna odpowiedź to D
