Odpowiedź :
a)
[tex]3 \frac{1}{6} - \frac{1}{3} = 3 \frac{1}{6} - \frac{2}{6} = 2 \frac{7}{6} - \frac{2}{6} = 2 \frac{5}{6} [/tex]
b)
[tex]6 \frac{1}{12} - 2 \frac{1}{2} = 6 \frac{1}{12} - 2 \frac{6}{12} = 5 \frac{13}{12} - 2 \frac{6}{12} = 3 \frac{7}{12} [/tex]
c)
[tex]5 \frac{1}{12} - 1\frac{2}{7} = 5 \frac{7}{84} - 1 \frac{24}{84} = 4 \frac{91}{84} - 1 \frac{24}{84} = 3 \frac{67}{84} [/tex]
d)
[tex]14 \frac{7}{18} - 11 \frac{12}{27} = 14 \frac{42}{108} - 11 \frac{48}{108} =13 \frac{150}{108} - 11 \frac{48}{108} = 2 \frac{102}{108} = 2 \frac{51}{54} [/tex]
Odpowiedź:
3 i 1/6 - 1/3 = 3 i 1/6 - 2/6 = 2 i 7/6 - 2/6 = 2 i 5/6
6 i 1/12 - 2 i 1/2 = 6 i 1/12 - 2 i 6/12 = 5 i 13/12 - 2 i 6/12 = 3 i 7/12
5 i 1/12 - 1 i 2/7 = 5 i 7/84 - 1 i 24/84 = 4 i 91/84 - 1 i 24/84 = 3 i 67/84
14 i 7/18 - 11 i 12/27 = 14 i 21/54 - 11 i 24/54 = 13 i 75/54 - 11 i 24/54 = 2 i 51/54 = 2 i 17/18