x - jeden bok
2x - drugi bok
Zapiszmy równanie:
[tex]35 = 2(x + 2x) \\ 35 = 2x + 4x \\ 35 = 6x | \div 6 \\ x = \frac{35}{6} = 5 \frac{5}{6} [/tex]
Jeden bok ma
[tex]5 \frac{5}{6} [/tex]
Drugi bok ma
[tex]5 \frac{5}{6} \times 2 = 10 \frac{10}{6} = 11 \frac{4}{6} = 11 \frac{2}{3} [/tex]
