Odpowiedź:
[tex]\begin{cases}3x-2y=6\ \ /\cdot3\\2x-3y=8\ \ /\cdot(-2)\end{cases}\\\\\\+\begin{cases}9x-6y=18\\-4x+6y=-16\end{cases}\\----------\\5x=2\ \ /:5\\\\x=\frac{2}{5}\\\\\\3\cdot\frac{2}{5}-2y=6\\\\\frac{6}{5}-2y=6\\\\-2y=6-\frac{6}{5}\\\\-2y=\frac{30}{5}-\frac{6}{5}\\\\-2y=\frac{24}{5}\ \ /:(-2)\\\\y=-\frac{\not24^1^2}{5}\cdot\frac{1}{\not2_{1}}\\\\y=-\frac{12}{5}\\\\\begin{cases}x=\frac{2}{5}\\y=-\frac{12}{5}\end{cases}[/tex]
