Odpowiedź:
A=11m²
q=598V
T1=110°C
λ1=15V/m*K
d1=8mm=0,008m
λ2=0,032V/m*K
d2=8mm=0,008m
λ3=0,092V/m*K
d3=20mm=0,02m
λ4=4,025V/m*K
d4=1mm=0,001m
q=ΔT*A*λ/d
d*q=ΔT*A*λ
ΔT=d*q/A*λ
ΔT1=0,008m*598V/11m²*15V/m*K
ΔT1=0,029°C
ΔT2=0,008m*598V/11m²*0,032V/m*K
ΔT2=13,6°C
ΔT3=0,02m*598V/11m²*0,092V/m*K
ΔT3=11,8°C
ΔT4=0,001m*598V/11m²*4,025V/m*K
ΔT4=0,0135°C
T2=109,971°C
T3=96,371°C
T4=84,571°C
T5=84,557°C