[tex]dla \ \ x = -3[/tex]
[tex]a) \ \frac{x+3}{x} = \frac{-3+3}{-3} = \frac{0}{-3} = 0\\\\b) \ -5x^{2}-x = -5\cdot(-3)^{2}-(-3) = -5\cdot9+3 = -45+3 = -42\\\\c) \ -2x+5 = -2\cdot(-3)+5 = 6+5 =11\\\\d) \ \frac{x+1}{x-1} = \frac{-3+1}{-3-1} = \frac{-2}{-4} = \frac{2}{4} = \frac{1}{2}[/tex]
