Odpowiedź:
a)
[tex]6 \div \sqrt{3 } = \frac{6}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{6 \sqrt{3} }{3} = {2 \sqrt{3} }[/tex]
b)
[tex]9 \div \sqrt{3} = \frac{9}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{9 \sqrt{3} }{3} = 3 \sqrt{3} [/tex]
c)
[tex]10 \div \sqrt{3} = \frac{10}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{10 \sqrt{3} }{3} [/tex]
d)
[tex] \sqrt{6} \div \sqrt{3} = \frac{ \sqrt{6} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{ \sqrt{18} }{ 3 } = \frac{3 \sqrt{2} }{3} = \sqrt{2} [/tex]
