Odpowiedź :
Cześć!
Obliczenia
[tex](x+2)(x-3)+(x-2)(x+3)=\\\\x^2-3x+2x-6+(x^2+3x-2x-6)=\\\\x^2-x-6+(x^2+x-6)=x^2-x-6+x^2+x-6=\\\\=x^2+x^2-x+x-6-6=\boxed{2x^2-12}[/tex]
(x+2)(x-3)+(x-2)(x+3) = x² - 3x +2x - 6 + x² + 3x - 2x - 6 = 2x² - 12
Cześć!
Obliczenia
[tex](x+2)(x-3)+(x-2)(x+3)=\\\\x^2-3x+2x-6+(x^2+3x-2x-6)=\\\\x^2-x-6+(x^2+x-6)=x^2-x-6+x^2+x-6=\\\\=x^2+x^2-x+x-6-6=\boxed{2x^2-12}[/tex]
(x+2)(x-3)+(x-2)(x+3) = x² - 3x +2x - 6 + x² + 3x - 2x - 6 = 2x² - 12