Zadanie 1
[tex]\dfrac{2+x}{3}-2x>\dfrac{1}{2}\ \mid\cdot6\\\\2(2+x)-12x>3\\\\4+2x-12x>3\\\\4-10x>3\\\\10x<1\\\\x<\dfrac{1}{10}\\\\\boxed{x\in\Big(-\infty,\dfrac{1}{10}\Big)}[/tex]
Zadanie 2
[tex](3-4x)^2\leq (4x-1)(4x+1)\\\\9-24x+16x^2\leq 16x^2-1\\\\9-24x\leq -1\\\\24x\geq 10\\\\x\geq\dfrac{5}{12}\\\\\boxed{x\in\Big\langle \dfrac{5}{12},+\infty\Big)}[/tex]
