[tex]a)~~(60t-8)\div 4 = \dfrac{60t}{4} -\dfrac{8}{4} =15t-2\\\\b)~~- \dfrac{6,3a+9}{3} = \dfrac{-6,3a-9}{3}=-\dfrac{6,3a}{3} -\dfrac{9}{3} =-2,1a-3\\\\c)~~-12\cdot \dfrac{y+7}{-4} =3\cdot (y+7)=3y+21\\\\d)~~\dfrac{x+10}{-16} \cdot 8=\dfrac{x+10}{-2}=\dfrac{x}{-2} +\dfrac{10}{-2} =-\dfrac{1}{2} x-5[/tex]
