[tex]dane:\\l = 10 \ m\\g = 10\frac{m}{s^{2}}\\szukane:\\T = ?\\f = ?[/tex]
Okres T:
[tex]T = 2\pi\sqrt{\frac{l}{g}}\\\\T = 2\cdot3,14\cdot\sqrt{\frac{10 \ m}{10\frac{m}{s^{2}}}}\\\\\underline{T = 6,28 \ s}[/tex]
Częstotliwość f:
[tex]f = \frac{1}{T}\\\\f = \frac{1}{6,28 \ s}\\\\\underline{f \approx0,16 \ Hz}[/tex]
